Perpendicular bisectors pass through the midpoint of a line segment, and run perpendicular to them.
\(4y=-3x+29\) or \(y=-\frac{3}{4}x+\frac{29}{2}\)
For more practice, try: Zeta Higher Textbook, Page 15, Exercise 1.8, Questions 1(a), 1(b) and 1(c)
A straight line equation must be rearranged to make \(y\) the subject (\(y=\dots\)) before its gradient can be determined.
\(2y=-x-5\) or \(y=-\frac{1}{2}x-\frac{5}{2}\)
For more practice, try: Zeta Higher Textbook, Page 13, Exercise 1.6, Questions 3, 4 and 5
The formula \(m=\tan{\theta}\) links a line's gradient to the angle it makes with the positive direction of the \(x\)-axis.
\(y=-x+2\)
For more practice, try: Zeta Higher Textbook, Page 9, Exercise 1.4A, Questions 1, 2 and 3
Calculate the gradients of PQ and QR first. The conclusion to a collinearity problem needs to be learned carefully.
\(m_{PQ}=m_{QR}=-3\), valid statement
For more practice, try: Zeta Higher Textbook, Page 12, Exercise 1.5, Questions 1(a), 1(b) and 1(c)
Medians meet opposite sides at the midpoint.
Altitudes meet opposite sides at an angle of 90 degrees.
You can use \(y=y\) as a first step to finding points of intersection.
\(y=-3x+5\)
\(2y=-x-5\) or \(y=-\frac{1}{2}x-\frac{5}{2}\)
\((3,-4)\)
For more practice, try: Zeta Higher Textbook, Page 21, Exercise 1.11B, Questions 1, 2 and 3
Calculate \(u_1\) first using the value of \(u_0\) as a starting point.
What is the value of \(a\)?
\(15\)
\(-1<a<1\), valid statement
For more practice, try: Zeta Higher Textbook, Page 90, Exercise 6.1, Questions 1(a), 1(b) and 1(c)
Can you put both \(u_2\) and \(u_3\) into the recurrence relation? Where does each one go?
What is the value of \(a\)?
\(-4\)
\(a>1\), valid statement
For more practice, try: Zeta Higher Textbook, Page 93, Exercise 6.3, Questions 1(f), 1(i) and 1(l)
Substitute the value of \(u_4\) into the recurrence relation.
Use your expression from part (a), and the new information that \(u_5=-1\).
\(6k-4\)
\(k=\frac{1}{2}\)
For more practice, try: Zeta Higher Textbook, Page 15, Exercise 1.8, Questions 1(a), 1(b) and 1(c)
What "12% is subtracted (from the original 100%) as a decimal?
Since dividing by \(0.12\) is tricky, multiply both parts of the fraction by \(100\) and work from there.
\(a=0.88,b-30\)
250 squirrels
For more practice, try: Zeta Higher Textbook, Page 96, Exercise 6.5B, Questions 1, 2 and 3
Create two equations: one linking the first two terms, and a second linking the second term and the third term. Solve simultaneously.
\(p=-\frac{1}{2},q=2\)
For more practice, try: Zeta Higher Textbook, Page 91, Exercise 6.2, Questions 1(a), 1(b) and 1(c)
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Start by using a formula to find the gradient between the points.Coming soon.
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